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Find the domain of f(x)=ln(1+lnx) Find the inverse of f(x) and its domain.
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the domain of the log is positive reals, i.e. \(x>0\) so in order for the outside function to exist, it must be the case that \(1+\ln(x)>0\) and \(x>0\)
right, so for f(x), x.0, got that part
\(1+\ln(x)>0\implies \ln(x)>-1\implies x>e^{-1}=\frac{1}{e}\)
x>0
which is your final answer, because if \(x>\frac{1}{e}\) it is already greater than zero
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whats the equation for the inverse function though?
@satellite73
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