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Mathematics 15 Online
OpenStudy (anonymous):

solve log5(5x-2)>log5(2x+10)

OpenStudy (armor):

First, you need to get rid of the logarithms. \[\log_5(5x-2)>\log_5(2x+10)\implies 5x-2>2x+10\]Can you finish it now?

OpenStudy (anonymous):

no idk how to do this:( its on my e2020 :/

OpenStudy (anonymous):

what is the answer?

OpenStudy (armor):

Can you try to finish it yourself?

OpenStudy (anonymous):

but idk how

OpenStudy (anonymous):

im sorry i really would try but i have no idea on this stuff :(

OpenStudy (armor):

\[5x-2>2x+10\]\[5x-2+2>2x+10+2\]\[5x>2x+12\]How about now? Just do a similar thing with the 2x.

OpenStudy (anonymous):

so 5x+2x > 12 7x > 12 ?

OpenStudy (armor):

Subtract the 2x instead of adding, but that's right idea.

OpenStudy (anonymous):

ahh four!!!!!

OpenStudy (anonymous):

omg thank you so much :')))

OpenStudy (armor):

You get \[5x>2x+12\]\[5x-2x>2x-2x+12\]\[3x>12\]\[x>4\]Precisely.

OpenStudy (armor):

You're welcome :)

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