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solve log5(5x-2)>log5(2x+10)
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First, you need to get rid of the logarithms. \[\log_5(5x-2)>\log_5(2x+10)\implies 5x-2>2x+10\]Can you finish it now?
no idk how to do this:( its on my e2020 :/
what is the answer?
Can you try to finish it yourself?
but idk how
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im sorry i really would try but i have no idea on this stuff :(
\[5x-2>2x+10\]\[5x-2+2>2x+10+2\]\[5x>2x+12\]How about now? Just do a similar thing with the 2x.
so 5x+2x > 12 7x > 12 ?
Subtract the 2x instead of adding, but that's right idea.
ahh four!!!!!
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omg thank you so much :')))
You get \[5x>2x+12\]\[5x-2x>2x-2x+12\]\[3x>12\]\[x>4\]Precisely.
You're welcome :)
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