i need help finding the domain of this function: r(p)=√2-5p
did you mean \[\sqrt{(2-5p)}\]
\[\sqrt{2} -5p\]
top one
solve this \[2-5p \ge 0\] because the value under the radical cant be negative
is it p>2/5 ?
-2 from both sides \[-5p \ge -2\]
divide by -5 \[p \le \frac{ 2 }{ 5 }\]
ok but why is this solved as an inequality?
because for radical equations the value under the radical sign has to be 0 or greater (because square root of negatives are not real numbers)
so the domain would be 2/5 ?
no its expressed as an inequality
okay so pretend the problem was r(p)=2-5p what would the domain be
so its \[p \le \frac{ 2 }{ 5 }\]
if it was that it would be all real numbers
rp = 2-5p I mean would be all reals for domain
the reason its an inequality is because radicals have to have number zero or over in the side because radicals of negatives are not real numbers
oh okay thank you i understand now!
great
Join our real-time social learning platform and learn together with your friends!