solve this plz √(x^(2)-3x) = 4x^(2)- 12 x leave answer in square root
Have you tried squaring both sides of the equation and calling x^2=s and solving the second order equation for s as you normaly do and taking the square root of s?
oh forget it, there are terms of order 1 and 3 so it wouldn't work
aha, found it. Call x^2-3x=y then the equation gets like this: \[\sqrt{y} = 4y\]Solve for y, then solve for x knowing y
it means √(y)=4y-12
No, only 4y because the right hand side is 4 times whats in the square root
sorry question is √(x^(2)-3x) = 4x^(2)- 12x - 3
Then it is \[\sqrt{y}=4y-3\]
√(x^(2)-3x) = 4x^(2)- 12- 3x
√(x^(2)-3x) = 4x^(2)- 12x - 3 (wrong)
Well then I guess my sugestion does not help.
Are you sure it is right? Because I tried putting it into mathematica and the exact solution was HUGE.
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