x^4-x^2-72/x^5+8x^3-27x^2-216

Question

anonymous · Answer

That's easier to read if you write it as an equation:
$$x^{4} - x^{2} - 72/x^{5} + 8x^{3} - 27x^{2} - 216$$

and put the terms in order by rank:
$$x^{4} - 8x^{3} - x^{2} + 27x^{2} - 216 - 72/x^{5}$$

and combine like terms:
$$x^{4} - 8x^{3} + 26x^{2} - 216 - 72/x^{5}$$

but we still don't know what you wanted to do with it. :)

anonymous · Answer

ill figure it out thx

anonymous · Answer

Oops I accidentally changed a sign on $$27x^{2}$$
The equation editor is still your friend, though.

anonymous · Answer

hey jireem u think u can help out in another problem i have?

anonymous · Answer

Maybe, fire away.

anonymous · Answer

alright hold up

anonymous · Answer

RJ's plumbing and heating charges 55$ plus 40$ per hour for emergency service. Gary remembers being billed over 150$ for an emergency call. how long was RJ's there?

anonymous · Answer

do u see it

anonymous · Answer

Sure. RJ's has a base charge ($55) and a hourly rate ($40).

The base charge + the hourly rate times the number of hours = the total. We'll use b for the base charge, r for the hourly rate, and h for the number of hours, and write this as an equation:
$$b + rh = total$$
Filling in the amounts we already know gives
$$55 + 40h = 155$$
Then we can solve for h (the number of hours), and know the minimum amount of time that RJ's must have spent on the call.

anonymous · Answer

oh ok thx i was a bit confused in this one but thx..

anonymous · Answer

Still confused? I trust the explanation helped, if not please let me know what was confusing.