who can check and tell me what i did wrong? :/ rationalize the denominator and simplify

Question

anonymous · Answer

attachment

anonymous · Answer

It's so blurry to my vision, can't tell 5 or 3 or 8 :(

anonymous · Answer

oh sorry ill try to make it bigger give me a sec pliz

hartnn · Answer

1st
$\huge \sqrt[3]{16}=2\sqrt[3]{2}$
ok?

hartnn · Answer

and $\huge\sqrt[3]{8}/\sqrt[3]{4}=\sqrt[3]{2}$
that should clear everything ..... ?

anonymous · Answer

attachment

hartnn · Answer

did u get my work ?

anonymous · Answer

not the second one... i understand it.. but i have 4r^2s^2t.. in the nominator.. why the cube root of 8 divided by 4?

anonymous · Answer

r the cube root of 4?

hartnn · Answer

oh, sorry cube root of 2 in denom.
which gives u cube root of 4 in num.....

hartnn · Answer

$\huge\sqrt[3]{8}/\sqrt[3]{2}=\sqrt[3]{4}$

anonymous · Answer

i still dont get it sorry...  i was thinking if i divide  8 and 16 by 4= 8/4=2 and 16/4=4 but in the answe i have 4/2?

hartnn · Answer

first of all u just took out 16 outside cube root..did u notice that?

hartnn · Answer

wouldn't it be $\sqrt[3]16$ ?

anonymous · Answer

yes, then i dont take them out neither in the denominator or nominator

anonymous · Answer

ok

hartnn · Answer

$\huge\frac{\sqrt[3]8}{\sqrt[3]16}=\frac{\sqrt[3]4}{\sqrt[3]8}=\frac{\sqrt[3]4}{2}$
making sense ?

anonymous · Answer

got it!:) thank you

hartnn · Answer

welcome :)