Question

Solve the equations x-y-5=0,
x^2+2xy+y^2
.
.
.
ANSWER={(4,-1),(1,-4)}

Answer 1

can u complete the question

Answer 2

x^2+2xy+y^2=?????

Answer 3

X^2+2XY+Y^2=9

Answer 4

First we have to eliminate one variable:
x-y=5 -->(A)
(x+y)^2= (x-y)^2+4xy=25+4xy=9

substitute x-y=5 in above, we get

xy=(9-25)/4=-4

=> y=-4/x

substitute this in (A), we get x+4/x = 5

x^2+4-5x=0
Now solve this to find x, and from (A) u can find y

Answer 5

X^2+2XY+Y^2=9 or (x+y)^2=9 thus taking sqaure toots u will have x+y=+3(eq2) or x+y=-3(eq3) let x-y=5 be eq1
now u have to solve two pairs simultaneously equations
viz 1 ....is x-y-5=0, and x+y=3 and 2.... x-y-5=0, and x+y=-3

now for 1
add eq1 and eq2 we have 2x=8 or x=4 hence putting x=4 in x+y=3
we have y=-1 thus (4,-1) is one of the answer
again for 2
add eq1 and eq3 we have 2x=2 or x=1 hence putting x=1 in x+y=-3
we have y=-4 thus (1,-4) is one of the answer

thus the answers are (4,-1) and (1,-4)