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OpenStudy (anonymous):
Vector Analysis : Find a vector equation for the line through (1,2) perpendicular to the line with vector equation r=7i+2j+t(3i+4j).
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OpenStudy (experimentx):
your line would be r = 1i + 2j + t(xi + yj) again you have x*3 + 4 *y = 0 you would get, 3x = -4y hence you line would be t(3xi+3yj) = -4y i +3yj = y(-4i+3j) so you line is i+2j+t(-4i+3j)
OpenStudy (anonymous):
thanks @experimentX
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