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Find the product of the complex number and its conjugate.
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3 + 3i
\((a+bi)(a-bi)=a^2+b^2\) a positive real number don't think about \(i\) or minus signs or let anything else distract you from this calculation. it is just \(a^2+b^2\) in your case it is \(3^2+3^2\)which you can do in your head
you dont do the foil thing
no you don't do a foiling thing if you do you will get the same answer, but it is not the easy way to do it. just \(a^2+b^2\) and that is all
this works for all the questions that ask find the product of the complex number and its conjugate?
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\((2+3i)(2-3i)=2^2+3^2\) \[(1+\sqrt{2}i)(1-\sqrt{2}i)=1+2\]etc
yes absolutely
so 18 and thanks
yw
can you help with another question i posted
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