The density of liquid oxygen at its boiling point is 1.14 \rm{kg/L} , and its heat of vaporization is 213 \rm{kJ/kg} .

How much energy in joules would be absorbed by 3.0 L of liquid oxygen as it vaporized?

Question

The density of liquid oxygen at its boiling point is 1.14 \rm{kg/L} , and its heat of vaporization is 213 \rm{kJ/kg} .

How much energy in joules would be absorbed by 3.0 L of liquid oxygen as it vaporized?

anonymous · Answer

Do you know the formula for heat needed by substance to change phase?

anonymous · Answer

would it be q=s*m*t

anonymous · Answer

The one I know Q=mU
where U is heat of vaporization.

anonymous · Answer

so it would it beQ= mass(40.7kj?mol)?

anonymous · Answer

U here =213 kJ/kg

anonymous · Answer

so u would * the 40.7kj/kg by 3.0L?

anonymous · Answer

Find the mass first