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Mathematics 15 Online
OpenStudy (anonymous):

Write the expression in standard form.

OpenStudy (anonymous):

5/3-15i

OpenStudy (anonymous):

thats a hard one for me to

OpenStudy (anonymous):

please someone help by giving me the answer i tried solving many times and failed

OpenStudy (anonymous):

what do you mean by standard form

Directrix (directrix):

A complex number is any number that can be written in the standard form a + bi, where a and b are real numbers and i is the imaginary unit.

Directrix (directrix):

I am thining that the answer options are not for this problem OR the problem is incorrectly written. 5/3-15i ---> (5/3) + (-15) i is standard form.

OpenStudy (anonymous):

thats exactly what it says

OpenStudy (anonymous):

5 ---- 3-15i

Directrix (directrix):

5 ---- 3-15i is not the same as 5/3 - 5/15i no more than 5 over (4 + 1) = 5/4 + 5/1. First, you'll need to rationalize the denominator of 3 - 15i by multiplying it and the numerator by the conjugate 3 + 15i.

OpenStudy (anonymous):

what do you think the answer is

OpenStudy (agent47):

Do what Directix told you: 5(3+15i) ------------ (3-15i)(3+15i) 5(3+15i) 5(3+15i) --------=--------- 9-25i^2 9 - 25(-1)

OpenStudy (agent47):

5(3+15i)/(9+25)=5(3+15i)/36=(15+75i)/36...

OpenStudy (agent47):

= (15/36) + (75i)/36 = = (5/12)+(25i)/12

OpenStudy (anonymous):

is the answer the second choice?

OpenStudy (agent47):

Mistake....

OpenStudy (agent47):

*****************5(3+15i)/(9+225)=

Directrix (directrix):

After multiplying by the conjugate, I got (15 + 75i)/(9 - 225 i^2) and simplified from there to the answer.

Directrix (directrix):

Factor a 3 out of the numerator and denominator and 5/78 + (25/78) i turns up.

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