Question

(3/x-2) - (2/x+4) = 1

Answer 1

do you mean \[\frac{ 2 }{ x-3 } - \frac{ 2 }{ x+4 } = 1\]

Answer 2

\[{3 \over {x - 2}}-{2 \over {x+4}}=1\]
Right?

Answer 3

okay

Answer 4

PhoenixFire, yes! My computer's being super slow.

Answer 5

Okay find the Common denominator? (x-2)(x+4)

Answer 6

and multiply both sides by it

Answer 7

Yep! I tried multiplying everything by (x-2) and (x+4).

Answer 8

\[(x-2)(x+4) \left[ \frac{ 3 }{ x-2 } - \frac{ 2 }{ x+4 } =1\right]\]

Answer 9

getting 3(x+4) - 2(x-2) = (x-2)(x+4)

Answer 10

That's exactly what I got!

Answer 11

3x+12-2x-4= Remember to foil this side

Answer 12

Got that!

Answer 13

it's 3x+12-2x+4... not -4

Answer 14

3x+12-2x-4= x`2 +2x-8

Answer 15

yeah

Answer 16

When I figured it all out, I ended up having to use the quadratic formula.
I got +4, too.

Answer 17

it's x + 16 = x`2 +2x-8

Answer 18

Got that!!

Answer 19

get everything on one side

Answer 20

x`2+x-24 = 0

Answer 21

Then, it's 0=x^2+x-24. You can't factor that, can you?

Answer 22

hmm it not easily factor-able so use quadratic formula

Answer 23

But, it's not a real solution, is it?

Answer 24

we can tell with the discriminate, it might be irrational number but not a nice clean answer

Answer 25

\[\sqrt{1^{2}-4(1)(-24)}\]

Answer 26

The question was to find all real values for x. I didn't think this was a real answer:\[\frac{ -1\pm \sqrt{97} }{ 2 }\]

Answer 27

when you say REAL do you mean Real Numbers, because irrationals are real numbers

Answer 28

True... I suppose I'll put that as my answer!

Answer 29

it would not be real if the radical was negative

Answer 30

I would

Answer 31

unless it was a approx answer like a decimal

Answer 32

Thank you! I'm glad I did it right! Lol.

Answer 33

good job, Its nice to see students doing math well

Answer 34

Yeah, I love whenever people help me and I help them with math. It's kinda fun!

Answer 35

I think so too

Answer 36

Thanks for the help! :)

Answer 37

NP