What is the value of the y variable in the solution to the following system of equations? 13x - 6y = 20 7x + 4y = 18 2 1 -2 -1
13x - 6y = 20.............i 7x + 4y = 18.............ii
Now, (20+6y)/13=(18-4y)/7
Now, substitute all the values and see which one satisfies
Does it help?
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Isolate both x's and use x1= x2 to solve for y
i got y = -2 - .6 :/
you guys did it a very complicated way^ i still don't understand..
Multiply both sides of 13x - 6y = 20 by 2 to get 13x - 6y = 20 2(13x - 6y) = 2*20 26x - 12y = 40 Multiply both sides of 7x + 4y = 18 by 3 to get 7x + 4y = 18 3(7x + 4y) = 3*18 21x + 12y = 54 So we now have the system 26x - 12y = 40 21x + 12y = 54
Add the equations 26x - 12y = 40 21x + 12y = 54 --------------- 47x = 94 and solve for x 47x = 94 x = 94/47 x = 2
Haha, I was too lazy to write all that.
then use this to find y 13x - 6y = 20 13(2) - 6y = 20 26 - 6y = 20 -6y = 20 - 26 -6y = -6 y = -6/(-6) y = 1
Oh i understand better now, why did you multiply both sides by 2 in the first step? how did you get that number. i didn't know you had to add the equations together either.
lol c=
that is called elimination. we use this method to eliminate either x or y. Since you wanted the y value of the system, he eliminated your x
I will post a couple of examples for you
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