Question

Shade the solution to the system of inequalities.
x < 2
_
y < 3x

Answer 1

Ahh... into two systems of inequalities now?

Answer 2

I'm guessing later it will be polygons of constraints. :)

Answer 3

not sure how to make that little line under the < sign on this page lol hope you understand what I was asking.
and yes...two systems now. ugh. lol

Answer 4

is the line under for the x< 2?

Answer 5

yes

Answer 6

Sure.

Answer 7

\[x \le 2\] and \[y < 3x\]

Answer 8

Now from here, graph one at a time. so if you know that x is less than or equal to 2, the make x always equal to 2. (x = 2)

so the line will be vertical.

Answer 9

The line is solid since there is the equal sign and you know that it is less than two so you shade left.

Answer 10

Now for y<3x,

If x is 0 then y is 0
If y is 0 then x is 0

(0,0)

Now you can plug in anything into the x to give you another set of coordinates.

Let x be 1.

y < 3(1)

y<3

(1,3)

This line is dotted and shaded down since it is less.

Answer 11

so it's (2,0) solid, and (1,3) dotted is what your saying for my ordered pairs?

Answer 12

Each equation is a line.

Answer 13

So you have two lines to draw.

Answer 14

The black is shading, the red line is your first system and the green line is your second system.

Answer 15

It's like the equation from before! Just do one at a time.

Answer 16

You rule! :)
Another one that I got right!

Answer 17

IF I had a tutor like you all class I'd pass for sure. LOL
The way you explain makes it so easy to understand. Half the time I get all upset going ''what do I do!?''
I may survive this class after all. 2 more weeks to go. :)

Answer 18

Haha, I'm here as often as I can. Just inbox me if you ever need more help or just tag me in your question.

Answer 19

Thanks so much! :)

Answer 20

Are you doing polygons of constraints this year?

Answer 21

More than likely later on in my second class.

Answer 22

Grade 11?

Answer 23

Algebra I & II. (College)
Math was NEVER my subject. LOL Or I wouldn't be here haha.

Answer 24

Oh, I see. You'll probably go even further than polygons of constraints but hey, I'm always available :)

Answer 25

Appreciate it alot!
Don't worry I am not afraid to ask questions. See you around. :)