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Mathematics
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Logarithmic Funtion
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\[\log_{2} (\frac{ 1 }{ 8 })\]
write 1/8 as \(\huge 2^{-3}\)
Okay and then what
Oh then the answer is -3
yabsolutely :)
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\[\log_{3} \sqrt{27}\]
I think same idea right?
yup, how can u write 27 ?
But I forget how to break that up
27^1/2 ?
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27 = 3*3*3 = 3^3 and \(\sqrt a= a^{(1/2)}\) so \(\sqrt{27}=27^{1/2}=3^{3/2}\)
did u get that last step ? 3^(3/2) ?
I kind of do but could you be more clear on that last step?
u were correct with \(\sqrt{27}=27^{1/2}\) now \(\sqrt{27}=(3^3)^{1/2}=3^{3/2}\)
ohh yea I get it haha
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okay so 3/2
great yes :)
Now I am having trouble with the derivatives of logarithmic functions
ask your question on a new post ....
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