A countrys population in 1991 was 231 million. In 1999 it was 233 million. Estimate the population in 2003using exponential growth formula. Round your answer to the nearest million. can somebody explain this to me please.
The population growth exponentially. P=Ae^(Bt) A and B are constant, P=population, t=time
see im taking plato and i havent even learn this so can you explain it in steps please?/;
t=1991 -> P=231 231=Ae^(B*1991) .................(1) t=1999 -> P=233 233=Ae^(B*1999)..................(2) from 1&2, you cn find A and B.
and when i find a and b what do i do?
You can find P when t=2003 using the very first equation.
im confused... sorry. /:
What class are you in?
credit recovery.
Were you able to find A and B?
no because i dont know how to do it. im new to it so it takes time... and i dont even know what im doing, so yeah..
let's make it a bit easier start time at 1991 1991 t=0 pop. is in millions \[231 =A*e ^{Bt} \] can you solve that if t=0?
what is \[e ^{0}\] ?
okay explain what is, because im using my phone..
You may need to review a bit http://tutorial.math.lamar.edu/Classes/CalcI/ExpFunctions.aspx
thank you.
Read that a couple times. Then see if you still need help with this problem.
okay.
would the answer be235 ?
close
darn, so i did it wrong
did you find A and B? show me those and I can check that work...
my friend at school showed me a way but im not to sure but what i did was: 1991=231 1999=232 2003=235 i got that by adding 2
screen shotted
i cant my phone is broken. wah i just subtracted 231&232.. then got 2 and then added to 232 and got 235.
You can't learn algebra by not learning algebra.
i know... its just hard because i have to learn it by a computer and none of my teachers wont help me...
>all of your teachers will help you
@Algebraic! agreed, all teacher will help, just ask nicely :)
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