Question

1 + 1 (n+1/n) + 3 (n+1/n)^2 + 5 (+1/n)^3...........
find the sum ???

Answer 1

Are there any other directions.?

Answer 2

what directions???

Answer 3

So you have to break the problem down into smaller bits...
Look at the first term. It has a leading 1 then the next term has a leading 3...

Answer 4

n-->infinity ?? hmm?

Answer 5

This will seem like you should have a formula , the first part anyway as, (1+(2)^n). Does that make sence?

Answer 6

Arithmaetico geometric series with common ratio (n+1)/n and common difference 2....and does n-> infinity ??
infinite terms ??

Answer 7

n ---> infinity./..

Answer 8

The second component is multiplied by the term like the above... It is also growing without bounds, right?

Answer 9

guys please check whether my logic is correct or not??

Answer 10

we write n+1/n = 1 + 1/n

when n----> infinity then
1/n = 0

so we can eliminate it

Answer 11

@hartnn @shubhamsrg check this

Answer 12

here's one formulla which you should remember in an AGP ..
(n->infinity)Sum = ab/(1–r) + dbr/(1–r)^2.

where, a= first term of AP
b= first term of GP
d=common difference of AP
r=common ratio of GP

this one has a simple derivation..nothing much to be worried about..
just plug in values..

Answer 13

why cant we do like this???

Answer 14

we can eliminate it in the first few terms ,ofcorse since the constant term is <<<<n
but it has infinite terms,,as you proceed adding, a time will come when the constant will not be negligible in front of n,, and you cant decide what no. that'll be,,so you cant just do like that..
hope i was clear,.

Answer 15

hmm. ok

Answer 16

1 (n+(1/n)) or 1 (n+1)/n ?

Answer 17

?

Answer 18

1(n+1/n)