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tan ( cos^-1 4/5 + tan^-1 2/3) = ?
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|dw:1347694111880:dw| any help ?
i mean does this help * ?
cos^-1 4/5 = 37
you didnt need to know that for this ques..
maybe......use first tan (A+B),then tan(cos^-1 x) = sqrt(1-x^2)/x
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cos^-1 4/5=tan^-13/4
hence the qn becomes tan(tan^-13/4+tan^-1 2/3)
yes you may do that,, what i was trying to state is from the fig, or otherwise , cos^-1 4/5 = tan^-1 3/4 on that subsn, use identity of tan^-1 a + tan^-1 b then its quite simple..
as @AravindG has stated already..
hw cos^-1 4/5=tan^-13/4 ???
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