if 2-cos^2 θ = 3sinθcosθ, sinθ not equal to cosθ, then tanθ is ?

1) 1/2
2) 0
3) 2/3
4) 1/3

Question

if 2-cos^2 θ = 3sinθcosθ, sinθ not equal to cosθ, then tanθ is ?

1) 1/2
2) 0
3) 2/3
4) 1/3

anonymous · Answer

ok so lets try to change this "2" into "2sin^2 + 2cos^2"

anonymous · Answer

and divide both sides of the equation by cos^2
what do we get ?

anonymous · Answer

are you there ?

anonymous · Answer

2 tan^2θ +1= 3tanθ   @coolsector

shubhamsrg · Answer

not 2 tan^2 @,,you get 2 sec^2 @ ..right?

shubhamsrg · Answer

and sec^2 @ = 1 + tan^2 @
use this and solve for tan @

anonymous · Answer

$$2-\cos^2 θ = 3\sinθ\cosθ$$divide by  $\cos^2 \theta$$$\frac{2}{\cos^2 θ}-1 = 3\frac{\sinθ\cosθ}{\cos^2 \theta}$$$$2(1+\tan^2 \theta)-1=3\tan \theta$$$$2\tan^2 \theta-3\tan \theta+1=0$$a quadratic in terms of $\tan \theta$

aravindg · Answer

oops i am late

anonymous · Answer

dhiwagm you got the same equation as mukushla got .. this is good..
he solved it completely anyway so nothing much for you to do