The probability of the empty set \[P(\emptyset )=\]
What does this mean
0
0
\[P \left( \emptyset \right) = 0\]
ok , but i dont undertand
I was guessing :P
well, yeah The probability of the empty set is zero , but what does this mean?
how can it be shown?
empty set is an impossible event
P(S) = 1 \[S \cup \emptyset = S\] \[S \cap \emptyset = \] so, \[S and \emptyset \] are mutually exclusive \[P \left( S \right) = P \left( S \cup \emptyset \right) = P \left( S \right) + P (\emptyset) \] \[P \left( S \right) = 1 ; \] \[1 = 1 + P (\emptyset) \] \[ P (\emptyset) = 0 \]
\[S \cap \emptyset =\emptyset \]
you have answered my question well, \[S∪∅=S\iff P(\emptyset)=0\]
to determine the probability you must have an event , is the empty set a lack of events
@UnkleRhaukus you are judging math by your preconditioned intuition. In fact probaility with sets has a generally unified (and mostly used) set of Kolmogorov foundation. Today this is the foundation used everywhere except in some esoteric and very rare circumstances. http://en.wikipedia.org/wiki/Probability_axioms
i am questioning not judging ,
Well empty set can be intuited differently - such event taht NO outcomes can make it truly occur. That is, the EventOccurenceTruthFunction(outcome) = False for all possible outcomes
empty set = false ?
=impossible = no solutions ?
Look up what is Truth Function. It characterizes "happened or did not happen"
For example TruthOdd(outcome 4) = False TruthOdd(outcome 3) = True
ok thanks
@UnkleRhaukus yes.., it's what I mean \[S \cap \emptyset = \emptyset\]
what do you mean by S and ∅ are mutually exclusive,
mutually exclusive events are events that cannot occur at the same time,
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