Question

Solve for x
the equation
x^4 + ax^3 - ab^2 -a^2b^2 = 0
here a,b, are considered KNOWN parameters

Answer 1

Answer in 3 minutes

Answer 2

Hint: factor in two parentheses

Answer 3

U posted the wrong question

Answer 4

Yeah. You missed an x somewhere.

Answer 5

yes lol

Answer 6

\[x^3(x+a)-ab^2(1+a)=0\]
\[x=1,x^3=ab^2\]

Answer 7

If u will factor this x^4 + ax^3 - ab^2 -a^2b^2 = 0 in 3years I MUST SAY U R GREAT

Answer 8

@Jonask what r u doing?

Answer 9

just realised,,its easier than it looks,,
direct ans is what @Jonask said..
which leads to what @sauravshakya said there and ultimately what @mukushla said,,hmm..
the range of my apologies inc,,ques should have ended 50-60 posts ago! hmm..

Answer 10

@Jonask Great - simple, and final.

Answer 11

Can u PLZ explain me

Answer 12

can you pin point there who said you did wrong and exactly what he said ? o.O

Answer 13

Oh got it

Answer 14

Explain what - the equation is in front of you SIR.

Answer 15

Howw???
Put x = 1.
=> (1+a) = ab^2(1+a) ... How is that true???

Answer 16

@Mikael , "SIR"? Explain

Answer 17

Check @Jonask

Answer 18

not 1,,he must have meant -a .. @Mikael posted the incorrect eqn..

Answer 19

abe kitna bada gadha hai tu !! attitude problem!! hmm.. :(

Answer 20

^^ Agreed, man.

Answer 21

and why x can't be negative ? is it length of something? what ?

Answer 22

all is correct vonjuch. dolbo-by

Answer 23

it corresponds to this silly thing :
http://openstudy.com/study#/updates/5051f753e4b02b4447c15384 @hartnn

Answer 24

This is from some geometric beginning @hartnn sorry

Answer 25

forgive him @hartnn !! :D

Answer 26

CAN SOMEONE EXPALIN ME WHAT @Jonask did

Answer 27

HE FACTORIZED (what was said)

Answer 28

What he did is wrong. The question is. The link Mikael gave has the correct question, and the correct, solution.

Answer 29

ok,ok.

Answer 30

@Jonask probably assumed it to be
x^4 + ax^3 - Xab^2 -a^2b^2 = 0
now its easily done..

Answer 31

How is @Jonask correct @Mikael

Answer 32

He solved the INTENDED equation @sauravshakya

Answer 33

kya bolta hai,khud hi bol ke khud hi samjh ke baith jata hai !!
am not gonna translate this one! :P

Answer 34

factorize and according to equality,\[x^3(x+a)=ab^2(1+a)\]
for the equation to be true\[x^3=ab^2,x=1\]

Answer 35

ohh,,since you did that,,,i'd its wrong..

Answer 36

i thought you by default assumed an x there..which made it correct with reference to
http://openstudy.com/study#/updates/5051f753e4b02b4447c15384 @hartnn

Answer 37

ohh sorry,,@hartnn was not intended in previous post! :P

Answer 38

nevermind,,i guess you should close the case now @Mikael

Answer 39

@siddhantsharan is correct in two remarks

Answer 40

Mudach'jo chernogzopoe otsasyvaet dvupolo