Question

show that the AM>=GM

Answer 1

AM is arithmetric mean,
GM is geometric mean

Answer 2

\[AM \ge GM\]

Answer 3

\[x _{1},x _{2},x _{3},...x _{n}\]
\[AM=\frac{ x _{1}+...+x _{n} }{ n }\]

Answer 4

\[GM=\sqrt[n]{x _{1}\times \times \times x _{n}}\]

Answer 5

eg
\[2,4,\]
\[AM=3,GM=\sqrt[]{8}\]
AM>GM

Answer 6

so many proofs

http://en.wikipedia.org/wiki/AM-GM

u can find more and more