what is the area of triangle whose two sides are 5 and one of the sides is 4 ??

Question

anonymous · Answer

u can use herons formula for that...

parthkohli · Answer

Heron was pretty cool for creating a formula like that :)

anonymous · Answer

i don't know that...i know this is an isosceles triangle :(

anonymous · Answer

s=(5+5+4)/2 = 7
so Area = $$\sqrt{s(s-a)(s-b)(s-c)}$$

anonymous · Answer

thanks...but this formula is so long and boring ...sorry :)

hartnn · Answer

lol!

hartnn · Answer

no other option i guess..

anonymous · Answer

kkk u know dat area of triangle = 1/2 * base * height

anonymous · Answer

1/2 b*h where height you get from pythogoras theorem and base is 4

hartnn · Answer

$\sqrt{s(s-a)(s-b)(s-c)}$
was better, seriously.

anonymous · Answer

so by constructing a perpendicular on the base of 4 cm and that perpendicular will bisect the side

anonymous · Answer

i am confused lol

ghazi · Answer

area = 2* (0.5*2*h) and h= sqrt 16-4

ghazi · Answer

$$h= 2\sqrt2$$

anonymous · Answer

UnkleRhaukus: Your response is incorrect. Please reread the question.

anonymous · Answer

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