Question

what is the area of triangle whose two sides are 5 and one of the sides is 4 ??

Answer 1

u can use herons formula for that...

Answer 2

Heron was pretty cool for creating a formula like that :)

Answer 3

i don't know that...i know this is an isosceles triangle :(

Answer 4

s=(5+5+4)/2 = 7
so Area = \[\sqrt{s(s-a)(s-b)(s-c)}\]

Answer 5

thanks...but this formula is so long and boring ...sorry :)

Answer 6

lol!

Answer 7

no other option i guess..

Answer 8

kkk u know dat area of triangle = 1/2 * base * height

Answer 9

1/2 b*h where height you get from pythogoras theorem and base is 4

Answer 10

\(\sqrt{s(s-a)(s-b)(s-c)}\)
was better, seriously.

Answer 11

so by constructing a perpendicular on the base of 4 cm and that perpendicular will bisect the side

Answer 12

i am confused lol

Answer 13

area = 2* (0.5*2*h) and h= sqrt 16-4

Answer 14

\[h= 2\sqrt2\]

Answer 15

UnkleRhaukus: Your response is incorrect. Please reread the question.