I need to rewrite this so that its a binomial:
\[e^{4t}+e^{2t}+2\]
is it even possible?
Yes :)
but how, I dont c it
Wait, I'm checking something. Just want to confirm if I'm giving the right info or not :)
lets say 2t = x and take it from there
What's on my mind is to apply factorization.
Knew it ;)
sorry lets say 2t = 1
\[e ^{2}+e+2\] is your equation.
or rather, your binomial
Factor it to get a binomial.
yea but how do I do that?
@dhatraditya that's transcendental, man.
have you ever factored a quadratic equation?
I hope I said it right, and yes I have. This one is just puzzling me right now
Is \(e\) a variable or the constant?
yeah?
\[e^{2t}\left( e + e^{2t}\right) + 2\]Is this a binomial, or no?
This is multivariable calc and I am trying to find the arc length. I get everything until I'm suppose to change the polynomial into a perfect square that it is easy to work under the radical. the original components of the vector was \[r(t)=<\sqrt{2}t, e^t, e^-t>\]
\[l=\int\limits_{a}^{b}\left| r'(t) \right|dt\]
Note, that is not an absolute value, it is magnitude
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