hi guys, i just want to know, in calculating limits, when I do direct substitution, and it gives 3/0, does it mean for sure that the limit does not exist?
not necessarily.... if you can simplify or reduce the function, do that first... then do direct substitution....
o-o
so after reduction, and it still gives 3/0, that means the answer is DNE right
yes.... you're right.
can you give me an example of where first direct substitution gives DNE, and after reduction the limit will exist?
ok.... lemme think...
\(\LARGE f(x)=\frac{x^2-1}{x+1} \) \(\LARGE \lim_{x \rightarrow -1} f(x) = -2 \)
ALRIGHT THANKS MATE U ARE DA BEST
here's an example, but actually, a direct substitution will give you an INDETERMINATE form 0/0... this is different from 3/0. you'll learn to deal with indeterminate forms later... so i think your first answer is correct.....:) yw....
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