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Mathematics 11 Online
OpenStudy (anonymous):

hi guys, i just want to know, in calculating limits, when I do direct substitution, and it gives 3/0, does it mean for sure that the limit does not exist?

OpenStudy (anonymous):

not necessarily.... if you can simplify or reduce the function, do that first... then do direct substitution....

OpenStudy (anonymous):

o-o

OpenStudy (anonymous):

so after reduction, and it still gives 3/0, that means the answer is DNE right

OpenStudy (anonymous):

yes.... you're right.

OpenStudy (anonymous):

can you give me an example of where first direct substitution gives DNE, and after reduction the limit will exist?

OpenStudy (anonymous):

ok.... lemme think...

OpenStudy (anonymous):

\(\LARGE f(x)=\frac{x^2-1}{x+1} \) \(\LARGE \lim_{x \rightarrow -1} f(x) = -2 \)

OpenStudy (anonymous):

ALRIGHT THANKS MATE U ARE DA BEST

OpenStudy (anonymous):

here's an example, but actually, a direct substitution will give you an INDETERMINATE form 0/0... this is different from 3/0. you'll learn to deal with indeterminate forms later... so i think your first answer is correct.....:) yw....

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