How do you work these types of problems out: Problem type A: √100 Problem type B: -√16 Problem type C: 1.1 ^ 2 Problem type D: (-18) ^2 Problem type E: √36 + √64
\[100=10\times 10\]
okay.
\[10\times10=10^2\]
alright.
type b?
@Jonask
please?
For B: \[4^2=16\] So th answer is -4
\[-(\pm4)=\mp4\]
i really dont get it
For C: It's easy.. You just do 1.1 * 1.1
i do not get b.
Aoh, You don't know the concept of square roots right?
no.
\[\sqrt{16}= \pm4\] \[-\sqrt{16}= -(\pm)4 = \mp4\]
B. is basically saying -1 * square root 16. Think what number multiplied by itself equals 16. Then multiply it by -1.
can i give yo the whole list of problems? this is really difficult for me.
a^2 = a*a a^2 = b The square root of "b" would be "a". "a" was squared in order to equal "b" so it's the sqaure root.
\[\sqrt{16} = \pm4\] but in general only principle value (i.e. +4) is taken. so if you consider only principle value then it is \[-(\sqrt{16})=-(4)=-4\]
Okay lets take B as an example. Find \[-\sqrt{16}\] Square of 16= 4^2=16 \[-\sqrt[2]{4^2}\] The square root always has the index 2 so just imagine that you're cancelling the index by the 2. |dw:1347732602816:dw|
Do you get it?!
-sigh- no.
couldnt you do a simpler explanation?
Simpler than that? What don't you get?
what grade are you in,aroub?
When you square a number (ex 10^2) you multiply it by itself: 10 * 10 10 * 10 = 100 so 10^2 = 100 The square root of 100 would be 10 because it was squared to equal 100. Do you understand? Problem type A: √100 10 * 10 = 100 so 10 is the square root. Problem type B: -√16 -1 * √16 4 * 4 = 16 so 4 is the suare root. 4 * -1 = -4 Problem type C: 1.1 ^ 2 What is 1.1 * 1.1? Problem type D: (-18) ^2 What is -18 * -18? Problem type E: √36 + √64 What # times itself equals 36? What # times itself equals 64? Add them together.
root = begining/source
i will try.
√67
What problem were you working on and how did you get the √67 ?
that is another problem
i will try jazy, then message u.
okay?
Sounds good, although I'm not very sure on how to work out √67
okay.
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