how do I match slices of level surface
you are going to have to be less vague ....
\[2x ^{2}+5y ^{2}+z ^{2}=4\] What is the graph when y=.75, z=1.5, y=0, and z=0
the function appears to be an elliptiod to start with; and we are allowing x to be any value|dw:1347731953894:dw|
the plane slice are ellipses too arent they
They are, I am looking for exactly what each of them looks like
the intersects are when we let 2 variable be zero and we solve for the remaining; 2x^2=4 ; x= +- sqrt(2) 5y^2=4 ; y = +- sqrt(4/5) z^2=4 ; z = +- sqrt(4) at y=0; z=0, we have an ellipse in the xy plane
the intercepts give us the dimensions we need to determine the elliptic equation\[(\frac{x^2}{a^2})^2+(\frac{y^2}{b^2})^2=1\]
"at y=0; z=0, we have an ellipse in the xy plane" Now I'm confused...
lol, well, I could be reading it askew ;) since the sqrt(10/5) is greater than the sqrt(4/5); this thing widen along the x axis; and half the widths is the values of a and b; and ignoreing the typo above .... \[\frac{x^2}{(\sqrt{2}/2)^2}+\frac{y^2}{(\sqrt{4/5}/2)^2}=1\] \[\frac{x^2}{1/2}+\frac{y^2}{4/10}=1\] \[2x^2+\frac 52 y^2=1\] \[4x^2+5 y^2=2\]
I think letting z and y both = 0 would be bad...you'd get a line?
im kinda confused about what "y=.75, z=1.5, y=0, and z=0" might mean tho
It's asking about level curves on certain planes like z=1.5 and so on... just plug in the value given and write it in standard form for an ellipse in the remaining variables...
so like on the plane z=1.5 you have an 'xy ellipse' to find the specific one, plug in z=1.5 and rearrange if necessary...
hmm, that does sound more cogent than the voices in my head :) thnx
:) love you, don't b& me.
kiki .... is that making better sense now?
I think so
Join our real-time social learning platform and learn together with your friends!