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Mathematics 5 Online
OpenStudy (anonymous):

What is the domain of the function f(x) = square root of x-2

OpenStudy (anonymous):

You cannot take the square root of a negative number and get a real answer.

OpenStudy (anonymous):

\[f(x) = \sqrt{x-2}\]

OpenStudy (anonymous):

Well it's a multiple answer and the choices are.

OpenStudy (anonymous):

Well, think about it. x-2 must be greater than or equal to 0, right?

OpenStudy (anonymous):

Ohh yeah, you can't square root negatives.

OpenStudy (anonymous):

Well, you can, but you do not get real results.

OpenStudy (anonymous):

Yeah and I need real.

OpenStudy (anonymous):

Correct. So x - 2 must be greater than or equal to 0. Solve the inequality for x.

OpenStudy (anonymous):

How do I know if it is x > or equal to 2 or 0<x< or equal to 2

OpenStudy (anonymous):

If its 0 < x < 2, this means x is greater than 0 and less than 2. This is not correct.

OpenStudy (anonymous):

\[x \ge2\] or\[0<x \le2\]

OpenStudy (anonymous):

Oh,

OpenStudy (anonymous):

So x is greater than or equal to 2 since it has to be a real number ,.

OpenStudy (anonymous):

The ONLY limitation is that you cannot take the square root of a negative number: |dw:1347734564181:dw|

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