Ask
your own question, for FREE!
Mathematics
7 Online
OpenStudy (anonymous):
What is the domain of the function f(x) = square root of x-2
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
You cannot take the square root of a negative number and get a real answer.
OpenStudy (anonymous):
\[f(x) = \sqrt{x-2}\]
OpenStudy (anonymous):
Well it's a multiple answer and the choices are.
OpenStudy (anonymous):
Well, think about it. x-2 must be greater than or equal to 0, right?
OpenStudy (anonymous):
Ohh yeah, you can't square root negatives.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Well, you can, but you do not get real results.
OpenStudy (anonymous):
Yeah and I need real.
OpenStudy (anonymous):
Correct. So x - 2 must be greater than or equal to 0. Solve the inequality for x.
OpenStudy (anonymous):
How do I know if it is x > or equal to 2 or 0<x< or equal to 2
OpenStudy (anonymous):
If its 0 < x < 2, this means x is greater than 0 and less than 2. This is not correct.
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[x \ge2\] or\[0<x \le2\]
OpenStudy (anonymous):
Oh,
OpenStudy (anonymous):
So x is greater than or equal to 2 since it has to be a real number ,.
OpenStudy (anonymous):
The ONLY limitation is that you cannot take the square root of a negative number:
|dw:1347734564181:dw|
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol:
i need help
18 hours ago
7 Replies
1 Medal