What is the domain of the function f(x) = square root of x-2
You cannot take the square root of a negative number and get a real answer.
\[f(x) = \sqrt{x-2}\]
Well it's a multiple answer and the choices are.
Well, think about it. x-2 must be greater than or equal to 0, right?
Ohh yeah, you can't square root negatives.
Well, you can, but you do not get real results.
Yeah and I need real.
Correct. So x - 2 must be greater than or equal to 0. Solve the inequality for x.
How do I know if it is x > or equal to 2 or 0<x< or equal to 2
If its 0 < x < 2, this means x is greater than 0 and less than 2. This is not correct.
\[x \ge2\] or\[0<x \le2\]
Oh,
So x is greater than or equal to 2 since it has to be a real number ,.
The ONLY limitation is that you cannot take the square root of a negative number: |dw:1347734564181:dw|
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