Question

(x-3)^3+8=0

Answer 1

add -8 to both sides

Answer 2

well i got to this part x^3-19=0

Answer 3

no

\[ \large (x-3)^3=-8 \]

Answer 4

k then

Answer 5

now take cubic roots of each side

Answer 6

x-3=2i?

Answer 7

yes

Answer 8

no
\[ \large \sqrt[3]{(x-3)^3}=\sqrt[3]{-8}=-2 \]

Answer 9

then u have
\[ \large x-3=-2 \]

Answer 10

ook so now why did you subtract 8 from both side instead of doing the parenthesis

Answer 11

if u had done that, in the end u would have had to use syntthetic division or something else to solve the equation. it is not a bad idea, but it is harder

Answer 12

so how do know when to do your method

Answer 13

how would i know when do apply your method

Answer 14

did they teach the order of operations?

Answer 15

nop

Answer 16

come on... for real??

Answer 17

oo my bad didnt read read the question right

Answer 18

well. take a look at this
\[ \large (7-3)^8+8= \]

Answer 19

tell me step by step how would u compute this

Answer 20

if i were do do this i would find the difference of the number in parenthesis, then raise the result to the 8th power and then add it to 8

Answer 21

great

Answer 22

to solve an equation u do that but in reverse order:
1st undo +8
2nd undo ^3
3rd undo -3
got it?

Answer 23

hmm

Answer 24

did they (your teachers) taught you this?

Answer 25

i dont remember something like this lol