Ask your own question, for FREE!
Mathematics 4 Online
OpenStudy (anonymous):

PLEASE HELP find the limit limf(X), where f(x)={x^2-4x+6, x<2 z-->2 {-x^2+4x-2, x>or greater than 2

hartnn (hartnn):

so u have 2 different definition of f(x) for two different range of x. which range contains x=2 ?

hartnn (hartnn):

the 1st one or the 2nd one ?

OpenStudy (noelgreco):

Evaluate each of the pieces of the piecewise function. If they're the same - that's the limit. I assume the z should be an x.

OpenStudy (anonymous):

both...?

OpenStudy (anonymous):

yeah thats my bad.. z is supposed to be x

OpenStudy (anonymous):

when you use right side limit, use upper function, and left sid limit, use below function

hartnn (hartnn):

nopes, not both. the first one has x<2...not equal. the 2nd one has x>=2....this contains x=, got it ?

hartnn (hartnn):

*x=2

OpenStudy (anonymous):

oh ok so the second one

OpenStudy (anonymous):

so the solving idea is mine. :)

hartnn (hartnn):

yup, now directly put x=2 in 2nd function, and tell me what u get?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

no his formula is when x goes to 2 find the limit of fuction so, it must investigate left and right limitation

hartnn (hartnn):

yes,thats correct.....that is your f(2) now u need to check whether f(2) equals left hand limit and right hand limit....if so then your limit value =2 if not then limit value does not exist. do u know how to find left hand and right hand limit ?

OpenStudy (anonymous):

it is not to find continuous ... just find left and right limit

OpenStudy (anonymous):

|dw:1347756393968:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!