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A particle with mass m at velocity v0, is hitting an identical particle(at rest, same mass), after that, two particle travel in different direction, va and vb, and the angle between two vectors. Provide that K/2<=Q<=0 (endothermic) Conservation of Energy 1/2mv^2+Q=1/2mva^2+1/2mvb^2 Conservation of Momentum mv0=mva+mvb Prove cos(theta)ab=-Q/(K+Q)
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Will need more information. Is there a diagram to go with this. In general if it's an elastic collision, kinetic energy is conserved; if inelastic, kinetic energy is not conserved. Linear momentum is always conserved regardless.
Looks like kinetic energy is not conserved since there is some heat loss, Q. Do you know what the angle between the two final velocity vectors is?
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