State the restrictions and simplify: 1/x-2 - 1/3x+4
\[\frac{ 1 }{ x-2 } - \frac{ 1 }{ 3x-4 }\]
@jim_thompson5910 can you help me with this
To subtract the fractions, you need to make sure the denominators are equal.
I got that and for some reason I am stuck I will draw what I have so you can tell me what I am doing wrong
alright go for it
|dw:1347762746080:dw|
ok one sec
i think you meant to say 3x-4 instead of 3x+4 right?
or is it really 3x+4 ?
no its 3x+4
ok let me make the fix on my steps then
what you have is correct Here's what I got \[\Large \frac{ 1 }{ x-2 } - \frac{ 1 }{ 3x+4 }\] \[\Large \frac{ 1(3x+4) }{ (x-2)(3x+4) } - \frac{ 1 }{ 3x+4 }\] \[\Large \frac{ 3x+4 }{ (x-2)(3x+4) } - \frac{ 1 }{ 3x+4 }\] \[\Large \frac{ 3x+4 }{ (x-2)(3x+4) } - \frac{ 1(x-2) }{ (x-2)(3x+4) }\] \[\Large \frac{ 3x+4 }{ (x-2)(3x+4) } - \frac{ x-2 }{ (x-2)(3x+4) }\] \[\Large \frac{ 3x+4 -( x-2) }{ (x-2)(3x+4) }\] \[\Large \frac{ 3x+4 -x+2 }{ (x-2)(3x+4) }\] \[\Large \frac{ 2x+6 }{ (x-2)(3x+4) }\] So \[\Large \frac{ 1 }{ x-2 } - \frac{ 1 }{ 3x+4 }\] simplifies to \[\Large \frac{ 2x+6 }{ (x-2)(3x+4) }\]
thats what I get
that's great
the questions says state the restrictions and simplify and the answer is the following|dw:1347763319732:dw| and the restrictions I understand are -4/3, 2 whic I can see how they get
I just figured it out
I can take 2 out of each top item
yes you can factor it out if you want
and the restrictions are in place to avoid division by zero
thank you it took working with someone to me to see it. I can't believe i didn't see it earlier. thanks
@jim_thompson5910 I can always rely on you thanks
you're welcome, glad to be of help
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