a square has a side of 10m. if you halve the two connecting sides, the area formed by the two connecting halves is what part of the whole square,.
I don't understand what you mean by: if you halve the two connecting sides
Hmm....so think about it this way, all sides are 10 m, so half of that would be 5. And connecting these to half marks would create a triangle, solve for the area of the square, then for the area of the triangle, then Area of triangle/Area of Square is your answer.
\[area=s ^{2}\] \[new area = (\frac{1}{2}s)^{2}\] \[new area=\frac{1}{4}s ^{2}\]
what will be the side of the square??
half of the side will be 5m but, the new square will be 25 m^2 which is one fourth of the original square's area of 100 m^2
am i going to use 5m??
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The question is slightly ambiguous, I thought the new shape is a triangle. |dw:1347765259370:dw|
So, by my interpretation it would be 1/4.... but @Eleven17 has a valid point... the shape is not defined in the question. His approx would be 1/8.
Right, @EulerGroupie , I agree that your solution is just as valid as mine based on the interpretation of the question.
Oh, the joys of discovery!
how i will solve it?
Its ambiguous.. I still have trouble with "the two connecting halves" from the question. Half of the area is 50 or half of the original.... very confusing question.
I think that they are trying to imply one quarter, but say it poorly. I like @Eleven17 's interpretation because it points out a major flaw in the question (I'm a rebel at heart). But, I bet they are looking for 1/4.
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