Question

State the restrictions and simplify:
1/x^2 + 1/x-2

Answer 1

\[\frac{ 1 }{ ^{x2} } + \frac{ 1 }{ x-2 }\]

Answer 2

Restriction: x must not =2.

Answer 3

To simplify, begin by combining the two terms. Hint: use the least common multiple as the denominator.

Answer 4

@jim_thompson5910 got another for ya

Answer 5

@allank

Answer 6

@jim_thompson5910

Answer 7

is it x-2 or x+2?

Answer 8

x-2

Answer 9

sorry my drawing I put x+2 in error

Answer 10

First, what do you think is the limitation for this?

Answer 11

that's ok

Answer 12

\[\Large \frac{ 1 }{ x^{2} } + \frac{ 1 }{ x-2 }\]


\[\Large \frac{ 1(x-2) }{ x^{2}(x-2) } + \frac{ 1 }{ x-2 }\]


\[\Large \frac{ x-2 }{ x^{2}(x-2) } + \frac{ 1 }{ x-2 }\]


\[\Large \frac{ x-2 }{ x^{2}(x-2) } + \frac{ 1*x^{2} }{ x^{2}(x-2) }\]


\[\Large \frac{ x-2 }{ x^{2}(x-2) } + \frac{ x^{2} }{ x^{2}(x-2) }\]


\[\Large \frac{ x-2 + x^{2} }{ x^{2}(x-2) }\]


\[\Large \frac{ x^{2} + x-2 }{ x^{2}(x-2) }\]

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So


\[\Large \frac{ 1 }{ x^{2} } + \frac{ 1 }{ x-2 }\]


simplifies to


\[\Large \frac{ x^{2} + x-2 }{ x^{2}(x-2) }\]

Answer 13

We're following the same idea as last time. The big difference this time we're adding instead of subtracting the fractions.

Answer 14

@jim_thompson5910 that is what I had but I was not seeing the bigger picture. I needed to rearrange it for x^2 to x to -2 so I can then factor it out. Ugg

Answer 15

you can factor x^2 + x - 2 to get (x+2)(x-1), but this is optional in my opinion

Answer 16

@jim_thompson5910 I really appreciate your help

Answer 17

yw, glad to be of help again