Question

You are traveling on an airplane. The velocity of the plane with respect to the air is 110.0 m/s due east. The velocity of the air with respect to the ground is 40.0 m/s at an angle of 30° west of due north.1) What is the speed of the plane with respect to the ground?2) What is the heading of the plane with respect to the ground? (Let 0° represent due north, 90° represents due east).(East of due North).3) How far east will the plane travel in 1 hour?

Answer 1

vpa=110 i
vag=-40 cos30 i + 40 sin30 j
1) vpg=vpa+vag
2) the heading: theta=tan-1(y/x) angle with respect to east direction.
3) try find (1) and (2) first :D

Is this helps you?

Answer 2

I found 1 and 2...how to i find 3?

Answer 3

Velocity = Change in position / change in time

Answer 4

i know that..thnks!

Answer 5

We have to make sure here that you use vpg to find the distance. Not vpa :)

Answer 6

I have to correct answer to 1, but I'm still having trouble finding 3. Can anyone help me?

Answer 7

1. Vpa = 180m/s. @ 0 deg.
Vag = 40m/s @ 120 deg,CCW.

Vpg = Vpa + Vag,
Vpg = (180 + 40cos120) + i40sin120,
Vpg = 160 + i34.64,
Vpg=sqrt((160)^2 + (34.64)^2)=163.7m/s.

2. tanA = Y / X = 34.64 / 160 = 0.2165,
A = 12.2 deg,CCW. = 12.2deg. North of
East.

3. 1 hr = 3600s.
d = Vt = 163.7m/s * 3600s = 589,320m.

Answer 8

Those are not the right answers