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Mathematics 4 Online
OpenStudy (anonymous):

Just need some clarification. I follow the even and odd part that in order to be even its 2k and odd is 2k+1. but where do they get the difference of 3 and 4? Each integer n>11 can be written as the sum of two composite numbers. Proof. Case 1: (n is even) Since n is even, n=2kfor some k≥6. Hence, n=2(k−3)+6 Case 2: (n is odd) Since n is odd, n=2k+1for some k≥5. n=2(k−4)+9 (The sum of two composites)

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