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Mathematics 10 Online
OpenStudy (anonymous):

Find two positive real numbers whose product is a maximum. The sum is A.

OpenStudy (anonymous):

is it be A/2 and A/2

OpenStudy (anonymous):

let the numbers be x and A-x hence their product =x(A-x)=xA -x^2=(A^2)/4 -(A^2)/4 +2xA/2 -x^2 =(A^2)/4 -(x-A/2)^2 thus the maximum value of the product is (A^2)/4 when the -ve part is 0 i.e when x=A/2 thus one number is A/2 and thus the other one is A-A/2=A/2

OpenStudy (anonymous):

\[xy= \max\]

OpenStudy (anonymous):

as A is a constant

OpenStudy (anonymous):

x + y = A y = A -x

OpenStudy (anonymous):

hence we can write xy = max as x*(A-x) = max

OpenStudy (anonymous):

xA - x2 = max

OpenStudy (anonymous):

now differentiating it A - 2x = 0 A = 2x

OpenStudy (anonymous):

and x = A/2

OpenStudy (anonymous):

and y = A - x y = A - A/2 y = A/2

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