Question

Integral with trig substitution. A bit stuck.... will post question.

Answer 1

\[\int\limits_{}^{} (8x+6)/(x^2+1) dx\]

I know that I need to to set u=arctan, but I'm stuck afterwards...

Answer 2

why not split the problem

\[\int\limits \frac{8x}{x^2 +1} + \frac{6}{x^2 + 1} dx\]

Answer 3

then you have a log function + an arctan

Answer 4

so you are looking at

\[ 4 \int\limits \frac{2x}{x^2 + 1} dx + 6 \int\limits \frac{1}{x^2 + 1} dx \]

Answer 5

split the problem as above and use the substitution rule of
\[\int\limits \] linear function / quadratic

Answer 6

ah ok that works :). Thank you both for the help... I just needed to split it up and it worked.