Find f '(x). f(x) =2x^2 ; a=1.
Has to be with f(x+h)-f(x)/h formula.
Show steps please.
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OpenStudy (anonymous):
1. expand 2(x+h)^2
OpenStudy (anonymous):
what do you get?
OpenStudy (anonymous):
2x^2+4xh+2h^2
OpenStudy (anonymous):
subtract 2x^2 from that
OpenStudy (anonymous):
{ f(x+h) -f(x) } done!
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OpenStudy (anonymous):
(2h^2 +4xh)/h
OpenStudy (anonymous):
common term?
OpenStudy (anonymous):
h
OpenStudy (anonymous):
2h
OpenStudy (anonymous):
'cancel' it
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OpenStudy (anonymous):
2h+4x
OpenStudy (anonymous):
\[\lim_{h \rightarrow 0} (2h+4x) = ..?\]
OpenStudy (anonymous):
4x
OpenStudy (anonymous):
done:)
OpenStudy (anonymous):
I love you
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OpenStudy (anonymous):
I love you too.
OpenStudy (anonymous):
I'm gonna try the next one by myself :D
OpenStudy (anonymous):
Can you answer this? Why is the derivative important?
OpenStudy (anonymous):
It's change. Change is important and sometimes positive.
OpenStudy (anonymous):
Even if it's negative, still good to understand it.
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OpenStudy (anonymous):
But couldn't we just find a point close to our original? Seem like the lim and secant line are unnecessary.
OpenStudy (anonymous):
Sure, but 4x is general, it works anywhere... why bother doing calculations for each point when you could just use something that works for every point.
OpenStudy (anonymous):
Right. Well ,I forgot there was a second part to the problem, which is: find the tangent line to the graph of y=f(x) at x=a
OpenStudy (anonymous):
you found the slope of any tangent line at any x (4x)...
at x=a =1 the slope of the tangent line is 4*1
a point which the tangent line goes through is (1 , 2(1)^2)
so now you know a point on the line and the slope of the line..
can you find the equation for the line?
OpenStudy (anonymous):
omg it is so easy!
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OpenStudy (anonymous):
Why didn't I see that?
OpenStudy (anonymous):
:)
OpenStudy (anonymous):
:(
OpenStudy (anonymous):
So let me see if I can figure the line out.
OpenStudy (anonymous):
I'm not getting the right equation. The answer in my book is y=4x-2
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
2 = 4*1 +b
b=-2
OpenStudy (anonymous):
I got y=4x
OpenStudy (anonymous):
y=4x -2
OpenStudy (anonymous):
y-4=4(x-1)
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OpenStudy (anonymous):
y-2 =4(x-1)
OpenStudy (anonymous):
point on the tangent line is the point on the original function where the tangent line 'hits' it = (1, 2*(1)^2) = (1,2)
OpenStudy (anonymous):
Whoops, I plugged the given number into f '(x) instead of f(x)
OpenStudy (anonymous):
so if a=2 my point would be 2,8, right?
OpenStudy (anonymous):
yep:)
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