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\[\sqrt{140}+\sqrt {50}+\sqrt {128}\]
You need to split each number into its prime factors. So for instance: |dw:1347806260067:dw| So \(140=2^2\times5\times7\) If we put this under the square root we have: \(\sqrt{140}=\sqrt{2^2\times5\times7}\) Now use the law that: \(\sqrt{ab}=\sqrt{a}\times\sqrt{b}\) So \(sqrt{140}=\sqrt{2^2}\times \sqrt{5\times7}\) And you can simplify the first to: \[2\sqrt{35}\]
Can you now apply this method to the others? You will no doubt end up with terms which can be collected.
|dw:1347806418000:dw| add them all
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