Question

An equation that goes through point (1.4) and is parallel to y=-3/4x+2?

Answer 1

suppose to be *-3/4x. yes i know the slope. I got a y= -3/4x +17/12. The book says y=-3/4x +19/4

Answer 2

so, the equation on the question is
\[y=-\frac{ 3 }{ 4 }x + 2\] ?

Answer 3

yea

Answer 4

i got 5/4 for y and -8/3 for x.... i don't see any other way to get another answer.

Answer 5

ahh.., the lines are parallel...
so, the slope is -3/4
since they are parallel, they have the same slope
then just use the formula

\[y-y _{1}=m \left( x-x _{1} \right)\]
\[(y _{1},x _{1})\] is the point

Answer 6

i did.... and i got a different answer from the book.

Answer 7

i solved for the new x and y, put them into point slope form, then i tried to check if it's correct in normal slope form, but my answer is not the same as in the book

Answer 8

\[y _{1} = 4 ; x _{1}=1\]
so,
y - 1 = (-3/4)(x - 1)
y = (-3/4)x + (3/4) + 1
y = (-3/4)x + 7/4

right?
*maybe the answer on the book is not correct :p

Answer 9

i think my x is wrong since i plugged in what i got for x and it isn't 4

Answer 10

no... why did you subtract y and 1? the y value given is 4...

Answer 11

nvm... x value is -8/3 and the y vaLaue is 5/4... however i still don't get 19/4

Answer 12

ahh..., I did a mistake..., sorry..
Yes.., it should be 4...,
sorry..

Answer 13

y - 4 = (-3/4)(x - 1)
y = (-3/4)x + (3/4) + 4
y = (-3/4)x + 19/4

Answer 14

oh ok thanks. i over complicated the problem

Answer 15

you're welcome... :)