Question

find the differential equation for the DE y=alpha(e^x)
+beta(e^2X)+delta(e^3x)

Answer 1

\[y=\alpha e^x+\beta e^{2x}+\delta e^{3x}\]

Answer 2

exactly ...jst that I could not write it in that way on the questions!!

Answer 3

let me give u the answer maybe u will be able to help out!!

Answer 4

are alpha, beta, delta functions of x?

Answer 5

y'''-6y''+11y'-6y=0 this is the answer given on the memo

Answer 6

what was the exact question

Answer 7

Find a differential equation for the given family of curves... that was one of the equations!!

Answer 8

so there are three constants , we must take the derivative three times

\[y=\alpha e^x+\beta e^{2x}+\delta e^{3x}\]
\[y'=\alpha e^x+2\beta e^{2x}+3\delta e^{3x}\]\[y''=\alpha e^x+4\beta e^{2x}+9\delta e^{3x}\]\[y'''=\alpha e^x+8\beta e^{2x}+27\delta e^{3x}\]

Answer 9

i dont know

Answer 10

nd then...
ow cool..let's jst wait maybe se1 else might crack it!

Answer 11

@mukushla

Answer 12

http://www.wolframalpha.com/input/?i=r%5E3+-6r%5E2+%2B11r-6&dataset=&asynchronous=false&equal=Submit

Answer 13

characteristic eqn. of the DE has the eigenvalues in the solution. You can expand (lambda -1)(lambda-2)(lamdba-3) to find the coefficients of the DE.

Answer 14

am still confused....
coz I have not done eigenvalues yet!!

Answer 15

\[ (D-1)(D-2)(D-3) y = 0\]
the standard solution of homogeneous constant coefficient DE

Answer 16

besides that ... you can eliminate the value of alpha, beta, delta from those three linear systems ... and put it into the original ... another system and get those values.

Answer 17

so I eliminate by using the 3 equations of derivatives?that sounds relevent?

Answer 18

yeah ... that is one of not so nice way that will always get you answer.

Answer 19

so the experiment thanks dawg I use the standard solution method and it's was just 2minute nd done!!