You have two empty bags and 100 bread rings. The goal is to put all your rings into the bags in such a way that one of the bags will contain exactly twice as many rings then the other.

You can't eat, break and lose the rings. All of them should go into the bags.

Question

You have two empty bags and 100 bread rings. The goal is to put all your rings into the bags in such a way that one of the bags will contain exactly twice as many rings then the other.

You can't eat, break and lose the rings. All of them should go into the bags.

asnaseer · Answer

is the fact that they are "rings" significant?

asnaseer · Answer

oh wait - I think I have it!

asnaseer · Answer

but I'll wait to see if others can find this - nice problem :)

asnaseer · Answer

the solution I have involves the bread rings

anonymous · Answer

$$A + B = 100         $$
$$A+B=100 = 2B + B = 3B = 100  B=\frac{ 100 }{ 3 }$$

But no this can't be.....we would have to break rings for this...

anonymous · Answer

Well I think I have a solution.What if we split the number of rings and put them in each bag and ten put one bag into another? :) In this way the condition is satisfied.Anyway it could've been simpler if the number of rings were 99.

asnaseer · Answer

yes - that is the solution I had as well

anonymous · Answer

@asnaseer Cheers!

parthkohli · Answer

@kartiksriramk has the correct solution :)