H1P3: Poor Workmanship
Joe wants to heat his 12'X20' workshop with electric heat. He has hired the HACME electrician company to build the system. They propose to use three W 240V baseboard heaters to provide a total heating capacity of W. (A heater is basically a resistor. This is not quite true, because there is a thermostatic switch incorporated into the heater and because the resistance of a heater varies a bit with its temperature. But we will use a linear resistor as a model of a heater.)
In the proposed system the heaters are connected in parallel with the 240V 60Hz AC po

Question

H1P3: Poor Workmanship
Joe wants to heat his 12'X20' workshop with electric heat. He has hired the HACME electrician company to build the system. They propose to use three       W 240V baseboard heaters to provide a total heating capacity of        W. (A heater is basically a resistor. This is not quite true, because there is a thermostatic switch incorporated into the heater and because the resistance of a heater varies a bit with its temperature. But we will use a linear resistor as a model of a heater.) 
In the proposed system the heaters are connected in parallel with the 240V 60Hz AC po

anonymous · Answer

http://openstudy.com/study#/updates/505616c5e4b02986d370dfa9 same question.

anonymous · Answer

$$R=V^{2}/Pt$$
$$i=V/R$$
In case of Vrms simply double the current.
To find out Power Dissipation first calculate the resistance using formula $$R=V^2/P$$ ('P' is simple power of one Resistor or Heater), After calculating this just use element law to add them up. one in series and two in parallel. Here you got total resistance (of mistaken circuit). Now just calculate the current of this circuit that is 
$$i=\sqrt{P/R}$$
To find out the power dissipated of first resistance i:e; H1 use this
$$P1=i^{2}R$$
for the second one use the same formula with the other values of R (Parallel One). After that just divide the answer by 2, because it's a parallel combination and current divides in parallel.