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f(x)= 3x squared -2x -6. Determine the minumum value.
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\[\text{If you mean this:}\\f(x)=3x^2-2x-6\] For f(x) to be minimum (or maximum), df/dx must be zero. Then: \[\frac{df(x)}{dx}=6x-2=0\\6x=2\\x=\frac13\]
I know its a mimumum because its positive. I just dont understand. it says the answer is minimum of -19/3
Try plug my answer to f(x) :)
im going to try :) thanks!
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