You are assigned to improve the blood donation process by reducing the wait time for donors. In order to plan the steps in the process you obtain a model for the flow of blood during the donation process. The following relationship is obtained: F = F0 (1 – C t) Where F = blood flow rate from donor to collection bag, ml/min F0 = initial blood flow rate, ml/min, found to have a typical value of 25 C is a constant, determined to be 0.022 min-1 T = time, min What amount of time should be allowed for the donation if the amount to be collected is 500 ml?
Say B is the amount of blood in ml.
\[\begin{align} B&=\int{F}dt \\&=\int{(F_0-Ct)}dt \\&=F_0t-\frac12 Ct^2 \\500&=25t-\frac12 0.22 t^2\end{align}\]
Can you find t from here?
might be able to
How would You cancel out the t's?
Would I Just subtract 25t to the other side then square root the left side of equation?
It's a quadratic equation. You can't just cancel t. Find t with this formula: \[at^2+bt+c=0\\then\\t=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
\[11t ^{2}-25t+500= 0\]
0.11
\[25+\sqrt{625-(220)}/.22\]
== 205.11
Correct!! There's another value actually :)
so now I just plug that in for t, correct?
That's the T you're looking for.In minutes.
True, thankyou very much. Appreciate it
No probs, I enjoy teaching stuff.
I noticed, was gonna ask if you were a teacher.
Yeah, i'm actually a rookie physics teacher.
gotta start somewhere. How did you know to make into a derivative?
From definition of rate, F=dB/dt so to find B, we must integrate F with respect to t. As we have done before.
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