Question

I need help!!!!!

The 20-g centrifuge at NASA's Ames Research Center in Mountain View, California, is a horizontal, cylindrical tube 58 ft long and is represented in the figure below. Assume an astronaut in training sits in a seat at one end, facing the axis of rotation 29.0 ft away. Determine the rotation rate, in revolutions per second, required to give the astronaut a centripetal acceleration of 19.8g.

Answer 1

\[a=\omega^2R\]
what's omega if a=19.8 g?

Answer 2

I have no clue....

Answer 3

i dont know what omega is?

Answer 4

Plug R=29.0 ft = .... m
and a=19.8*9.8 = .... m/s
into
\[a=\omega^2R\]
then find omega

Answer 5

I got 2.98... that doesnt sound right though

Answer 6

Mine was 4.685 rad/s
Must convert to rev/s
1 rev=2pi rad
So my final answer will be: 0.75 rev/s

Answer 7

I'm really not sure how you did that I am doing

SQRT(((19.8)(9.8))/29)

Answer 8

and that gives me 2.98

Answer 9

You must convert 29 ft into metres first.

Answer 10

Dude can you just give me the steps im really not getting it here

Answer 11

R=29 ft = 29*0.3048 m=8.84 m
a=19.8*9.8 m/s^2=194 m/s^2
omega=sqrt(a/R)=sqrt(194/8.84)=4.68 rad/s

Now we convert it to rev/s
1 rev=2pi rad or 1 rad=1/2pi rev
So:
4.68 rad/s=4.68/2pi rev/s=0.75 rev/s

Is it helping??

Answer 12

Ya, thanks man I'm really not trying to be rude I just have a full load this semester with work and school and its driving me crazy

Answer 13

No probs :) I love teaching stuffs.