Question

2+i/3-2i

Answer 1

multiply with the conjugate of 3-2i??

Answer 2

multiply numerator and denominator with 3+2i

Answer 3

The same question with mapelletah. If it's (2+i)/(3-2i),then it can be calculated as follow:
(2+i)/(3-2i)=[(2+i)*(3+2i)]/[(3+2i)*(3-2i)]=(4+7i)/13

Answer 4

i multiplied it and got 6+4i+3i+2i?

Answer 5

2+i(3+2i)

Answer 6

nope, it should be 6+4i+3i+2i^2
6+10i-2 as i^2=-1

Answer 7

how do you get 10i?

Answer 8

sry typing error 7i

Answer 9

6+7i^2?

Answer 10

6+7i-2

Answer 11

in back of the book it say (4/13)+(7/13i)

Answer 12

*says

Answer 13

6-2+7i is numerator

denominator is ( 3-2i)*(3+2i)=9-(4i^2)=9+4=13

Answer 14

which is exactly the answer just think a bit

Answer 15

excuse me?
i get how you got 9 from multiplying them but how did you get 4 from 9-(4i^2)?

Answer 16

i^2=-1
so 4i^2=-4
we have 9-4i^2=9+4=13

Answer 17

thanks

Answer 18

does that help

Answer 19

alot better

Answer 20

great