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OpenStudy (anonymous):
For the following reaction, identify the element that was oxidized, the element that was reduced, and the reducing agent. Give an explanation for each answer. SnCl2 + PbCl4 SnCl4 + PbCl2
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OpenStudy (anonymous):
SnCl2 + PbCl4 --> SnCl4 + PbCl2 Oxidized number of Sn is +2, become +4 --> oxidation Oxidized number of Pb is +4, become +2 --> reduction
OpenStudy (anonymous):
Oxidation is gaining oxygen and reduction is losing oxygen.
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