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x^-3+y^-6/x^-6y^-2
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\[\frac{x^{-3}+y^{-6}}{x^{-6}y^{-2}}\]?
same as \[(x^{-3}+y^{-6})\times x^6y^2\]
*y^2, sry
\(y^2\) in the denominator?
yes
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\[(x^{-3}+y^{-6})\times x^6y^{-2}\] would be a start
add the exponents, right?
yes you would get \[x^3y^{-2}+x^6y^{-8}\]then maybe \[\frac{x^3}{y^2}+\frac{x^6}{y^8}\]
if your goal is to make it one fraction you could add up and get \[\frac{x^3y^6+x^6}{y^8}\] not sure what the answer is supposed to look like
thanks, i was adding x^6y^-8
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yw
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